By the way, I was thinking through my explanation of why a single burnt out bulb makes a flasher flash faster.
I don't think it's right, and am hoping someone can come up with a working explanation.
You have 3 bulbs in parallel with each other, and then a flasher unit in series with all of them.
In parallel, any path to ground, no matter how resistive, still makes for lower overall resistance than not having it.
So if a bulb burns out, total resistance will go up, won't it?
Which blows a hole in my thinking that a burnt bulb would mean higher current through the flasher, and faster flashing as it heats up more quickly.
Since in fact total resistance will end up being higher, and less current passing through the flasher.
What am I missing?
I don't think it's right, and am hoping someone can come up with a working explanation.
You have 3 bulbs in parallel with each other, and then a flasher unit in series with all of them.
In parallel, any path to ground, no matter how resistive, still makes for lower overall resistance than not having it.
So if a bulb burns out, total resistance will go up, won't it?
Which blows a hole in my thinking that a burnt bulb would mean higher current through the flasher, and faster flashing as it heats up more quickly.
Since in fact total resistance will end up being higher, and less current passing through the flasher.
What am I missing?
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